What percentage of the class scored between a 67% and an 83%

anyalong18

New member
The exam scores for a particularly difficult math test had a mean score of 75% with a standard deviation of 8%. Approximately what percentage of the class scored between a 67% and an 83%.

Prove It

Well-known member
MHB Math Helper
Assuming this is a normal distribution, these scores are each within one standard deviation from the mean, so the percentage is...?

Country Boy

Well-known member
MHB Math Helper
I'm sure you know, if you are taking a course in which a question like this is asked, that you do NOT "calculate" the answer but look it up in a table of the "Standard Normal Distributio". Surely there must be one in your text book but there are also several on line.

There is a good one at normal distribution table - Bing images

The standard normal distribution has mean 0 and standard deviation 1. With mean 75 and standard distribution 8, (x- 75)/8 corresponds to x.

So a score of 67 corresponds to (67- 75)/8=-8/8= -1 and a score of 83 corresponds to (83- 75)/8= 8/8= 1.

Those scores are, as Prove It said, one standard deviation off the mean. In the table, you look up z= 1 and, because of the symmetry, the "z-score" for -1 is the negative of that. x- (-x)= 2x so the probability is just 2 times the value you looked up.

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