- #1
ehrenfest
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car 2 is twice as long as car 1 when they are at rest
a stationary policeman observes that car 2 is the same length as car 1 as car 2 passes car 1 going through a speed trap.
car 1 is going 1/2 the speed of light
I tried to solve this with
L 1/sqrt(1-(1/2)^2) = 2L/sqrt(1-v^2/c^2) and I got an imaginary anwer
a stationary policeman observes that car 2 is the same length as car 1 as car 2 passes car 1 going through a speed trap.
car 1 is going 1/2 the speed of light
I tried to solve this with
L 1/sqrt(1-(1/2)^2) = 2L/sqrt(1-v^2/c^2) and I got an imaginary anwer