- #1
B4cklfip
- 18
- 0
- Homework Statement
- Given is the Hamiltonian H of a n particle system and it should be shown that H and P commucate, thus [H,P] = 0.
Where P is given as $$P = \sum_{n=1}^N p_n.$$
- Relevant Equations
- $$H = \sum_{n=1}^N \frac{p_n^2}{2m_n} +\frac{1}{2}\sum_{n,n'}^N V(|x_n-x_n'|)$$
I have insertet the equations for H and P in the relation for the commutator which gives
$$[H,P] = [\sum_{n=1}^N \frac{p_n^2}{2m_n} +\frac{1}{2}\sum_{n,n'}^N V(|x_n-x_n'|),\sum_{n=1}^N p_n]
\\ = [\sum_{n=1}^N \frac{p_n^2}{2m_n},\sum_{n=1}^N p_n]+\frac{1}{2}[\sum_{n,n'}^N V(|x_n-x_n'|),\sum_{n=1}^N p_n]$$
The first term should become zero, but what about the second term? I don't really know how to go on here.
$$[H,P] = [\sum_{n=1}^N \frac{p_n^2}{2m_n} +\frac{1}{2}\sum_{n,n'}^N V(|x_n-x_n'|),\sum_{n=1}^N p_n]
\\ = [\sum_{n=1}^N \frac{p_n^2}{2m_n},\sum_{n=1}^N p_n]+\frac{1}{2}[\sum_{n,n'}^N V(|x_n-x_n'|),\sum_{n=1}^N p_n]$$
The first term should become zero, but what about the second term? I don't really know how to go on here.
Last edited by a moderator: