- #1
sachin123
- 121
- 0
A chain of length L,mass M kept vertical so it just touches ground.A height x of it from bottom falls down.Find the total force exerted by it on ground.
My attempt:
Force due to its weight=Mg
Force due to falling and change in momentum:
consider small element dy at height y
Change in momentum when it falls:M X root(2gy)
on integrating M X root(2gy) within limits 0 and x and dividing the integral by total time taken I get an expression.On adding it to Mg,I don't get the right answer.
Answer is:
3Mgx/L
Can someone help?Thanks
My attempt:
Force due to its weight=Mg
Force due to falling and change in momentum:
consider small element dy at height y
Change in momentum when it falls:M X root(2gy)
on integrating M X root(2gy) within limits 0 and x and dividing the integral by total time taken I get an expression.On adding it to Mg,I don't get the right answer.
Answer is:
3Mgx/L
Can someone help?Thanks