- #1
snoopy82
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Homework Statement
A golfer hits a shot to a green that is elevated 3.00 m above the point where the ball is struck. The ball leaves the club at a speed of 17.3 m/s at an angle of 50.0˚ above the horizontal. It rises to its maximum height and then falls down to the green. Ignoring air resistance, find the speed of the ball just before it lands.
Homework Equations
v^2 = v0^2 + 2ax
The Attempt at a Solution
Basically, what i did was getting the y value from the speed.
It was like: 17.3sin(50.0) = 13.25m/s. From the given, what
I could figure out were acceletion (-9.81m/s) and velocity (13.25m/s)
Since I only knew those two, I thought that I must use v^2 = v0^2 + 2ax.
For the maximum height, I did 0 = (13.25)^2 + 2(-9.81)(x) and x was 8.948m.
However, there was 3.00 elevation, so I subtracted 3.00 from 8.948,
which was 5.948m. From this, I tried to do the same equation and I
got the 10.80m/s for the answer, but the internet site says that it is wrong.