What is the Simplified Form of This Trigonometric Identity?

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In summary, the left-hand side of the given identity can be simplified to \sin(A)\left(1+\cos\left(\frac{2\pi}{3}\right)+\cos\left(\frac{4\pi}{3}\right)\right)+\cos(A)\left(\sin\left(\frac{2\pi}{3}\right)+\sin\left(\frac{4\pi}{3}\right)\right). This can then be further simplified by evaluating the values of 1+\cos\left(\frac{2\pi}{3}\right)+\cos\left(\frac{4\pi}{3}\right) and \sin\left(\frac{2\pi}{3}\right
  • #1
Silver Bolt
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$\sin\left({A}\right)+\sin\left({A+\frac{2\pi}{3}}\right)+\sin\left({A+\frac{4\pi}{3}}\right)=0$

$L.H.S=\sin\left({A}\right)+\left(\sin\left({A}\right)\cos\left({\frac{2\pi}{3}}\right)+\cos\left({A}\right)\sin\left({\frac{2\pi}{3}}\right)\right)+\left(\sin\left({A}\right)\cos\left({\frac{4\pi}{3}}\right)+\cos\left({A}\right)\sin\left({\frac{4\pi}{3}}\right)\right) $

From there?
 
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  • #2
You've only given an expression...what is the actual identity to be verified?
 
  • #3
Corrected now
 
  • #4
Silver Bolt said:
$\sin\left({A}\right)+\sin\left({A+\frac{2\pi}{3}}\right)+\sin\left({A+\frac{4\pi}{3}}\right)=0$

$L.H.S=\sin\left({A}\right)+\left(\sin\left({A}\right)\cos\left({\frac{2\pi}{3}}\right)+\cos\left({A}\right)\sin\left({\frac{2\pi}{3}}\right)\right)+\left(\sin\left({A}\right)\cos\left({\frac{4\pi}{3}}\right)+\cos\left({A}\right)\sin\left({\frac{4\pi}{3}}\right)\right) $

From there?

I would write the LHS as:

\(\displaystyle \sin(A)\left(1+\cos\left(\frac{2\pi}{3}\right)+\cos\left(\frac{4\pi}{3}\right)\right)+\cos(A)\left(\sin\left(\frac{2\pi}{3}\right)+\sin\left(\frac{4\pi}{3}\right)\right)\)

Now, what are:

\(\displaystyle 1+\cos\left(\frac{2\pi}{3}\right)+\cos\left(\frac{4\pi}{3}\right)=?\)

\(\displaystyle \sin\left(\frac{2\pi}{3}\right)+\sin\left(\frac{4\pi}{3}\right)=?\)
 

Related to What is the Simplified Form of This Trigonometric Identity?

What does it mean to "prove the identity" in science?

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