- #1
Lauren Wright
- 2
- 0
Homework Statement
You accidentally knock a full bucket of water off the side of the well. The bucket plunges 13 m to the bottom of the well. Attached to the bucket is a light rope that is wrapped around the crank cylinder. The cylinder has a radius of 0.085 m and inertia of 4.0 kg. The inertia of the bucket plus water is 12 kg.
How fast is the handle turning when the bucket hits the bottom?
the answer should be in terms of Wv (unit s^-1)
Homework Equations
V(omega)=s/r (where s is distance traveled around circle and r is radius)
Wv(rotational velocity)=(change in V)/(change it time)
Wv=(Vt (tangential velocity))/r
Ac (centripetal acceleration)=(V^2)/r
Ug(gravitational potential energy)=mgh (where h is change in height)
K=1/2(I)(Wv)^2
I=(mR^2)/2 (where R is radius and I is the rotational inertia of a cylinder)
*there could be more but I think I covered everything
The Attempt at a Solution
https://goo.gl/ILj9hk <----- url for a picture of my work, ignore bottom page, it is for a different problem
I know the answer is not 8.14 s^-1, which is what I originally got[/B]
Last edited: