- #1
ahero4eternity
- 10
- 0
A square metal plate 0.180 meters on each side is pivoted about an axis through point O at its center and perpendicular to the plate.
Calculate the net torque about this axis due to the three forces shown in the figure if the magnitudes of the forces are F1 = 18.0 N F2 = 27.0 N and F3 = 14.0 N. The plate and all forces are in the plane of the page.
Torque = Force x Length
Length = 1/2 x 0.180
Torque = radius x F sin theta
T1 (1.62) - T2 (2.43) - T3 (1.26) = -2.07
Shouldn't T1 be positive since it is going in the CW direction, while T2 and T3 are negative since they are going in the CCW direction? Where am I going wrong?