- #1
akirez
- 4
- 0
Homework Statement
A capacitor with two parallel plates of area 88.5 cm2 and nylon (dielectric strength 14 MV/m) inserted between them breaks down when a potential difference of 5.80 kV is applied. What is the maximum charge the plates will hold when the nylon is removed and the space filled with air (dielectric strength 3 MV/m)?
Homework Equations
Q = CΔV
ΔV = Ed
Co = εoA/d
Coκ = εoAκ/d
E = Eo/κ
The Attempt at a Solution
The maximum electric field with the nylon inserted is 14 MV/m. ΔV = Ed and we have 5800 V applied.
Solving for d gives d = 0.00041429 m.
The maximum electric field once the nylon removed is 3 MV/m. ΔV = Ed.
Solving for ΔV gives ΔV = 1242.87 V.
C = εoA/d gives C= 1.89*10^-8 F.
Q = CΔV = (1.89*10^-8 F)(1242.87 V) = 0.0000235 C.
The online assignment page is rejecting my answer. Where am I going wrong?
Last edited: