What is the field outside the shell?

In summary, a point charge Q at the center of a conducting spherical shell of radius R creates a field in the region between the point charge and the shell, given by E = -\frac{kQ}{R^2}. The field outside the shell can be found using Gauss's Law, where the total charge enclosed by a surface surrounding both the shell and the point charge is considered.
  • #1
tandoorichicken
245
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A point charge Q is at the center of a conducting spherical shell of radius R. The total charge of the shell is -Q. (a) What is the field in the region between the point charge and the shell? (b)What is the field outside the shell?

I think I got part (a): [tex] F = \frac{kq_1 q_2}{r^2} = \frac{kQ(-Q)}{R^2} = -\frac{kQ^2}{R^2} [/tex]
[tex] E = \frac{F}{Q} = -\frac{kQ}{R^2} [/tex]

Not quite sure how to do part (b) though.
 
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  • #2
Try it using Gauss's Law.

[tex]\int_S \boldsymbol{E}\cdot d\boldsymbol{A} = \frac{Q}{\epsilon_0}[/tex]

What's the total charge enclosed by a surface surrounding both the shell and the point charge?

On a similar account, I suggest having another look at part (a). Try it with Gauss's Law! Gauss makes life easy, not hard.

cookiemonster
 
  • #3


The field outside the shell can be found using Gauss's Law, which states that the electric flux through a closed surface is equal to the enclosed charge divided by the permittivity of free space. In this case, the enclosed charge is still -Q, and the permittivity of free space is a constant denoted by ε0. Therefore, the electric flux outside the shell can be expressed as:

Φ = Q/ε0

Since the electric flux is also equal to the surface integral of the electric field over the closed surface, we can set up the following equation:

Φ = ∫E•dA = E∫dA = E(4πR^2)

Solving for E, we get:

E = Q/(4πε0R^2)

This means that the electric field outside the shell is directly proportional to the charge Q and inversely proportional to the square of the distance from the center of the shell. It also does not depend on the radius of the shell itself, as long as the point charge is at the center.

In summary, the field outside the shell is given by the equation E = Q/(4πε0R^2), where Q is the charge of the point charge and R is the distance from the center of the shell. This field is always directed away from the shell, as the charge on the shell is negative and will repel any positive charges outside the shell.
 

Related to What is the field outside the shell?

What is the field outside the shell?

The field outside the shell refers to the electric field that is present outside a charged spherical object, such as a conducting shell.

How is the field outside the shell calculated?

The electric field outside the shell can be calculated using the formula E = kQ/r^2, where k is the Coulomb's constant, Q is the charge on the shell, and r is the distance from the center of the shell to the point where the field is being measured.

Is the field outside the shell uniform?

No, the field outside the shell is not uniform. It varies depending on the distance from the center of the shell and the location of the point where the field is being measured.

What happens to the field outside the shell if the shell is hollow?

If the shell is hollow, the electric field outside the shell will be the same as if all the charge on the shell was concentrated at its center. This is known as the "shell theorem."

Is the field outside the shell affected by the material of the shell?

No, the field outside the shell is not affected by the material of the shell. It only depends on the charge and distance from the center of the shell.

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