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Homework Statement
There's an elastic collision between a photon of energy E and an atom in an excited state. After the collision, the energy of the photon is still E but its direction changed of angle of 180° and the atom is now going back with velocity Bc. If the atom is in his ground state after collision, what was the excitation energy ? Give the answer in fonction of E, Bc, and mass rest mo
Homework Equations
The Attempt at a Solution
Conservation of energy:
E+m'c²=E+γmc²
We are supposed to find β=2E/(4E²+c²²m²) But I really don't see how we can get to that result
When we find β we just have m"excited"=m'-m=γm-m
Thanks