What is the correct answer to this simple maths problem?

  • Thread starter nokia8650
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As for the final run, it is at 22:45 and it is the 12 runs from 21:14 to 22:45 that I was counting. I don't know how else to explain it. But if you are correct about the meaning of "then every 10 minutes" then you are also correct that my count of 71 is wrong. That should be 72. So the total is 2+ 72+ 2+ 12+ 1= 89 runs.
  • #1
nokia8650
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http://img372.imageshack.us/img372/2057/timezy9.jpg

See image above. The answer is D - 88, however I can only find 84! Please can someone let me know what I am missing:

20-7= 13
13*6 + 1 = 79 = total upto 2030
+ 2045 bus = 80

+ 4 buses (two in 21st hr, two in 22nd hr) = 84

Thanks
 
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  • #2
Looks straight forward to me. First there are the two morning runs. Then it runs "every 10 minutes" from 8:30 to 20:30 (8:30 A.M. to 8:30 P.M.). That's 12 hours and 6 times an hour for 12 hours is 72 times- actually 71 since we are counting exactly at 8:30 separately. Then 2 more runs until 21:14 (9:14 P.M.). Then 12 runs between 21:14 and 22:45 culminating in the final run. A total of 2+ 71+ 2+ 12+ 1= 88 runs.
 
  • #3
Thanks for the reply. Isn't it every 10 minutes from 7:30 to 20:30, not from 8:30 to 20:30, which gives 79 runs up until the 20:30 run. Also, how are there "12 runs between 21:14 and 22:45 culminating in the final run?"

Thanks
 
  • #4
I was interpreting "then every 10 mins" as meaning from the END of the first two runs. You are interpreting it as 10 min after the start of the second run. I can't say which interpretation is correct.
 

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