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#### karush

##### Well-known member

- Jan 31, 2012

- 2,771

The linear speed is $\displaystyle\frac{16.53 \text{ ft}}{\text{sec}}$

What is the angular velocity $(\omega)$ in $\displaystyle\frac{\text{rev}}{\text {hr}}$

from $v=r\omega$ then

$\displaystyle\frac{16.53\text{ ft}}{\text{sec}}

\cdot\frac{3600\text {sec}}{\text {hr}}

\cdot\frac{1}{6.685\text{ in}}

\cdot\frac{12\text { in}}{\text {ft}}

\approx\frac{106821\text{ rev}}{\text{hr}}$

this ans looks to large???