- #1
siimplyabi
- 9
- 0
1. The
problem statement, all variables and given/known data
A pair of blocks are connected by a massless rope and placed on a frictionless surface. The diagram shows the situation at the instant the blocks are released. The left side has a mass of 35 kg and an incline of 25 degrees to the horizontal. The right side has a mass of 20 kg and an incline of 40 degrees to the horizontal.
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My attempt was solving each blocks acceleration by doing
Σf(+x)= Fgsin(theta)=ma
fg = mg there fore mgsin(theta)=ma
the masses cancel out leaving
gsin(theta)=a
so acc of block 1 =
(9.8m/s^2)(sin(25))=4.142 m/s^2
Should I not be canceling the masses out?
Would a better approach be taking mgsin(25)-mgsin(40)/55 = 0.345s?
problem statement, all variables and given/known data
A pair of blocks are connected by a massless rope and placed on a frictionless surface. The diagram shows the situation at the instant the blocks are released. The left side has a mass of 35 kg and an incline of 25 degrees to the horizontal. The right side has a mass of 20 kg and an incline of 40 degrees to the horizontal.
Homework Equations
[/B]
The Attempt at a Solution
My attempt was solving each blocks acceleration by doing
Σf(+x)= Fgsin(theta)=ma
fg = mg there fore mgsin(theta)=ma
the masses cancel out leaving
gsin(theta)=a
so acc of block 1 =
(9.8m/s^2)(sin(25))=4.142 m/s^2
Should I not be canceling the masses out?
Would a better approach be taking mgsin(25)-mgsin(40)/55 = 0.345s?