What is the Critical Density in the Context of Universe Expansion?

Additionally, the critical density can also be calculated using the exact escape velocity equation, which results in a similar equation for ρc, further supporting its importance in understanding the expansion of the universe. In summary, the critical density is a key factor in determining the fate of the universe and is calculated using various equations and constants.
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Definition/Summary

The critical density is defined to be the density necessary to asymptotically halt the expansion of the universe (i.e. flat or euclidean), slightly less and the universe is 'open' (hyperbolic or saddle shaped), slightly greater and the universe is 'closed' (spherical).

Equations

Einstein field equations (EFE)-

[tex]G_{\mu\nu}+g_{\mu\nu}\Lambda=\frac{8\pi G}{c^4} T_{\mu\nu}[/tex]

[itex]G_{\mu\nu}[/itex] is the Einstein tensor of curvature (spacetime), [itex]g_{\mu\nu}[/itex] is the metric tensor, [itex]\Lambda[/itex] is the cosmological constant, [itex]8\pi[/itex] is the concentration factor and [itex]T_{\mu\nu}[/itex] is the energy tensor of matter (matter energy).

Friedmann equation-

[tex]H^2=\frac{8 \pi G}{3} \rho - \frac{k c^2}{a^2}+\frac{\Lambda c^2}{3}[/tex]

where H is a function of time (in this case, the inverse of Hubble time), G is the gravitaional constant, [itex]\rho[/itex] is density in [itex]kg/m^3[/itex], k is the spatial curvature parameter (-1 to +1, -k is hyperbolic, 0 is flat and +k is hyperspherical), a is the time-scale factor (0 to 1, now being 1) ([itex]k/a^2[/itex] being the spatial curvature in any time-slice of the universe) and [itex]\Lambda[/itex] is the cosmological constant. (G, [itex]\Lambda[/itex] and c are universal constants, k is a constant throughout a solution and H, [itex]\rho[/itex], and a are a function of time. a is established by [itex]a=1/(1+z)[/itex] where z is the redshift.

Critical density equation-

[tex]\rho_{c}=\frac{3H^2}{8\pi G}[/tex]

where [itex]\rho_c[/itex] is the critical density.

Extended explanation

Einstein field equations (EFE)-

[tex]G_{\mu\nu}+g_{\mu\nu}\Lambda=\frac{8\pi G}{c^4} T_{\mu\nu}[/tex]

c and G are introduced to convert the quantity (which is expressed in physical units) to geometric units (G/c4 is used to convert units of energy into geometric units while G/c2 is used to convert units of mass, when mass is used instead of energy, the c4 is replaced with c2).

Using the EFE to establish Λ (presuming that gμν=1)

[tex]\Lambda =\frac{8\pi G}{c^4}u_{\Lambda}\ \equiv\ \ \frac{8 \pi G}{c^2}\rho_{\Lambda}[/tex]

where uΛ is vacuum energy and ρΛ is vacuum density (basically, uΛ=ρΛ·c2)

The equation is more commonly known as-

[tex]\rho_{vac}=\frac{\Lambda c^2}{8\pi G}[/tex]

where ρvac is essentially ρΛ

Critical density (ρc)-

The critical density is derived from the Friedmann equation-

[tex]H^2=\frac{8 \pi G}{3} \rho - \frac{k c^2}{a^2}+\frac{\Lambda c^2}{3}[/tex]

substituting for Λ, the equation can be rewritten-

[tex]
\begin{align*}
H^2&=\frac{8 \pi G}{3} \rho - \frac{kc^2}{a^2}+\frac{8 \pi G}{3}\rho_{\Lambda}\\

&=\frac{8 \pi G}{3} (\rho+\rho_{\Lambda}) - \frac{kc^2}{a^2}
\end{align*}
[/tex]

where [itex]\rho_c=(\rho+\rho_{\Lambda})[/itex], ρ representing baryonic and dark matter, ρΛ representing dark energy.

if we considered a flat universe, then k=0 and the equation can be reduced to-

[tex]H^2=\frac{8 \pi G}{3} \rho_c[/tex]

rewriting the equation relative to ρc, the critical density for a flat universe is-

[tex]\rho_{c}=\frac{3H^2}{8\pi G}[/tex]

Based on a Hubble constant of ~70 (km/s)/Mpc, a critical density of 0.918x10-26 kg/m3 is equivalent to 0.825 joules per km3.


Another short hand derivation based on exact escape velocity (i.e. kinetic energy cancelling out gravitational potential) is-

[tex]E=0=\frac{1}{2}v^2-\frac{Gm}{r}[/tex]

[tex]\Rightarrow v_{esc}=\sqrt{\frac{2Gm}{r}}[/tex]

if m is rewritten as-

[tex]m=V\rho[/tex]

where V is volume of a sphere [itex]V=(4/3)\pi r^3[/itex] and substitute-

[tex]v_{esc}=\sqrt{\frac{8\pi G}{3}\rho r^2}[/tex]

substituting for Hr=v (multiplying the inverse of Hubble time by the radius of the observable universe equals c) which would imply ρ=ρc-

[tex]Hr=\sqrt{\frac{8\pi G}{3}\rho_c r^2}[/tex]

[tex]H^2r^2=\frac{8\pi G}{3}\rho_c r^2[/tex]

[tex]H^2=\frac{8\pi G}{3}\rho_c[/tex]

rearrange relative to ρc-

[tex]\rho_{c}=\frac{3H^2}{8\pi G}[/tex]

* This entry is from our old Library feature. If you know who wrote it, please let us know so we can attribute a writer. Thanks!
 
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  • #2
Hi there! The critical density is the density necessary to asymptotically halt the expansion of the universe. This is determined using the Friedmann equation and Einstein field equations, which are used to calculate the cosmological constant Λ, the vacuum energy uΛ, the vacuum density ρΛ, and the critical density ρc. Substituting for Λ in the Friedmann equation results in an equation that can be rewritten relative to ρc, giving us the critical density equation: ρc=3H2/(8πG). Using a Hubble constant of ~70 km/s/Mpc, this yields a critical density of 0.918x10-26 kg/m3, which is equivalent to 0.825 joules per km3.
 

1. What is critical density?

Critical density is a concept in cosmology that refers to the density of matter and energy required for the universe to be flat. In other words, it is the density at which the expansion of the universe will eventually stop.

2. How is critical density calculated?

Critical density is calculated by dividing the total mass and energy of the universe by its volume. This value is then compared to the observed density of the universe to determine if it is above or below the critical density.

3. Why is critical density important?

Critical density is important because it has implications for the fate of the universe. If the actual density of the universe is less than the critical density, it will continue to expand indefinitely. If it is greater than the critical density, the universe will eventually collapse in on itself.

4. What is the current estimate of the critical density of the universe?

The current estimate of the critical density of the universe is approximately 9.9 x 10^-30 grams per cubic centimeter. This is equivalent to about 5.9 protons per cubic meter.

5. How does the concept of critical density relate to dark matter and dark energy?

The concept of critical density is closely related to dark matter and dark energy, as these are the two main components that make up the total mass and energy of the universe. Dark matter is thought to contribute significantly to the total mass of the universe, while dark energy is thought to be responsible for the observed acceleration of the universe's expansion.

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