- #1
OrlandoLewis
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Homework Statement
Consider one rod of length L which is spun at its center perpendicular to its length; it will have a certain moment of inertia. Now, if the same rod is folded in the middle creating a certain angle and still spun at its center, what happens to its moment of inertia?
Homework Equations
Thin rod about axis through center perpendicular to length
$$I = \frac{1}{12}ML^2$$
Thin rod about one edge
$$I = \frac{1}{3}ML^2$$
The Attempt at a Solution
For a rod that is not folded its moment of inertia will be:
$$\frac{1}{12}ML^2$$
For a folded one, I tried using L to be the length divided by two so:
$$I = 2(\frac{1}{3}\frac{M}{2}(\frac{L}{2})^2) = \frac{1}{12}ML^2$$
So the moment of inertia will be the same.
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