- #1
riseofphoenix
- 295
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What equations can I use to find the tension in this cable?? "Transverse pulse"??
I know I'm given the following but I have no idea what equation to use...does anyone know?
Mass: m = 0.180 kg
Length: L = 4.20 m
Tension: T = ? N
1) Equation to use: v = √(T/μ)
2) First find v and μ
v = distance/time
v = 2(4 trips)/0.845 s
v = 8/0.845
v = 9.467
valong the cord = 9.467(L)
valong the cord = 9.467(4.20 m)
valong the cord = 9.467(4.20 m)
valong the cord = 39.76331361 m/s
μ = m/L
μ = (0.180 kg)/(4.20 m)
μ = 0.042857
3) Plug everything in equation v = √(T/μ) and solve for T
(v)2 = [√(T/μ)]2
v2 = T/μ
μv2 = T
0.042857(39.763313612) = T
0.042857(1581.121109) = T
67.76210738 = T
67.8 N = T
Did I have the equations right??
I know I'm given the following but I have no idea what equation to use...does anyone know?
Mass: m = 0.180 kg
Length: L = 4.20 m
μ = mass (m) / unit length of cord (L)
Time for 4 trips down and back: 0.845 sTension: T = ? N
1) Equation to use: v = √(T/μ)
2) First find v and μ
v = distance/time
v = 2(4 trips)/0.845 s
v = 8/0.845
v = 9.467
valong the cord = 9.467(L)
valong the cord = 9.467(4.20 m)
valong the cord = 9.467(4.20 m)
valong the cord = 39.76331361 m/s
μ = m/L
μ = (0.180 kg)/(4.20 m)
μ = 0.042857
3) Plug everything in equation v = √(T/μ) and solve for T
(v)2 = [√(T/μ)]2
v2 = T/μ
μv2 = T
0.042857(39.763313612) = T
0.042857(1581.121109) = T
67.76210738 = T
67.8 N = T
Did I have the equations right??
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