sin(30)v should be squaredJiJiasd said:
Shouldnt this be mu*(m*g*cos(30))*h/cos(30)=mu*m*g*h?JiJiasd said:
What equation you did use ? thankssidt36 said:
I tried with 0,5*m*(sin(30)*v)^2 - mu * m*g*cos(30) = m*g*hReplusz said:
Now I tried 0,5*m*(sin(30)*v)^2 - mu * m*g*cos(30) *h/sin(30) = m*g*hReplusz said:
The formula for calculating the distance a block slides is d = 0.5 * μ * m * g * t^2, where d is the distance, μ is the coefficient of friction, m is the mass of the block, g is the acceleration due to gravity, and t is the time.
The coefficient of friction plays a significant role in determining the distance a block slides. A higher coefficient of friction means that there is more resistance to motion, so the block will not slide as far compared to a lower coefficient of friction.
Yes, the distance a block slides is affected by its mass. The greater the mass of the block, the more force is required to move it, so it will slide a shorter distance compared to a block with a smaller mass.
The angle of the incline plays a role in determining the distance a block slides. A steeper incline will result in a shorter distance, as there is more resistance to motion. A shallower incline will result in a longer distance, as there is less resistance to motion.
Yes, there are other factors that can affect the distance a block slides. These include the surface the block is sliding on, the presence of any external forces, and the shape or size of the block.