- #1
Darth Frodo
- 212
- 1
Homework Statement
[itex]\frac{3x + 1}{2x - 6}[/itex] < 3
Homework Equations
The Attempt at a Solution
[itex]\frac{3x + 1}{2(x -3}[/itex] < 3
[itex]\frac{3x +1}{x - 3}[/itex] < 6
Assume x < 3
3x + 1 > 6(x - 3)
3x + 1 > 6x - 18
3x + 1 - 6x + 18 > 0
19 > 3x
x < 19/3
No Contradiction.
Assume x > 3
3x + 1 < 6x - 18
3x - 19 > 0
3x > 19
x > 19/3
No Contradiction
How do I know which set of values to take?