WaveLengths of Light Waves and their respective photons

In summary, the device switches on and off at 1/2 a wavelength intervals, which causes a chopper to increase the bandwidth of the system. This in turn causes the emitted light to have a wider range of frequencies.
  • #1
user3
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Suppose you have a source of light that emits light with a wavelength of 2 meters, and you set the device to be turned on and switched off alternately. You also set it so that each interval the device is turned on is only long enough for 1 meter to be emitted (1/2 a wavelength). Do you ever observe any photons?
 
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  • #2
Since photons can be modeled as point particles ... the answer is yes.

And if your detector provides an energy spectrum, it will always give the energy for one of these photons.
 
  • #3
This question is absurd, if the photons emitted have wavelength of 2 meters, then we assume that source can emit only 2meters(wavelegth) photons. Its not like in shorter time shorter wavelengths come out and in longer time longer one`s come out, radiation is discreet!

We must also understand how photons are produced, they are generally through de-excitation of electrons in energy levels, however only visible photons can be produced that way, for wavelengths of 2 meters(VHF-range), they use other methods, but photons are discreet and the wavelength output does not depend on the on/off time. The delta-t, will affect only the spectral width.

I hope it helped.
 
  • #4
UltrafastPED said:
Since photons can be modeled as point particles ... the answer is yes.

And if your detector provides an energy spectrum, it will always give the energy for one of these photons.
How does the alternate switching affect photon density? If it has no effect, can it be used to reduce power consumption at transmission antennas?
 
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  • #5
sugeet said:
This question is absurd, if the photons emitted have wavelength of 2 meters, then we assume that source can emit only 2meters(wavelegth) photons. Its not like in shorter time shorter wavelengths come out and in longer time longer one`s come out, radiation is discreet!

We must also understand how photons are produced, they are generally through de-excitation of electrons in energy levels, however only visible photons can be produced that way, for wavelengths of 2 meters(VHF-range), they use other methods, but photons are discreet and the wavelength output does not depend on the on/off time. The delta-t, will affect only the spectral width.

I hope it helped.

I did not say shorter time intervals produce shorter wavelengths. Instead, I said it they will produce fractions of a wavelength.
 
  • #6
user3 said:
Suppose you have a source of light that emits light with a wavelength of 2 meters, and you set the device to be turned on and switched off alternately. You also set it so that each interval the device is turned on is only long enough for 1 meter to be emitted (1/2 a wavelength). Do you ever observe any photons?

For a wavelength of λ the time for a complete cycle is Δt=λ/c=1/frequency.

Your device has a shutter that cycles open-close twice during Δt.

You must first check your assumptions-start with classical electromagnetic radiation: if the wavelength/frequency is fixed then the emitter must be running continuously - you understand why this is true?

Your "chopper" will then increase the bandwidth of the system - this is a consequence of the time-bandwidth theorem, which is a very general result for classical waves. The details of how it does so varies with the physical setup, but it always takes place.

As you increase the speed of the chopper the bandwidth continues to increase; if the emitter is inside a cavity (enclosed space) the radiation that does not escape will accumulate ("rattle around") inside the cavity. Eventually it will reach some equilibrium state - and your device will approach that of a black body.

You can actually build a small radio transmitter (or buy one) and test this. If it was a laser experiment I would use an electrooptic shutter; you will have to find something else for radio waves.


With this classical description in mind, a quantum optical model can be built.

What should we expect? For a system which is periodically excited and then emits a single photon - I think your detector will sometimes click, and sometimes not.
 
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  • #7
In my opinion, this depends on what kind of device you are using to make system shut down and switch on. if this device is in the laser cavity, well, your laser-system must very efficient to observe the light, because the photon only passes the gain medium once and then should be blocked by your device. If it is put outside the cavity, you device is just a chopper. and yes, you will observe the laser coming out, just the number of the photon is small, and the bandwidth is very large.
 
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  • #9
DrDu said:
And, btw, a photon does not need to have a definite frequency.


It's the first time that I have been told that. How is that? What about this E = h f ?

Please elaborate
 
  • #10
user3 said:
It's the first time that I have been told that. How is that? What about this E = h f ?

Please elaborate

That is a consequence of the superposition principle. If a photon can exist as red or green monochromatic light, also a superposition of the two is a valid (but time dependent) quantum state for a photon.
E.g. a photon emitted by an atom is never monochromatic but a wavepacket formed from different frequencies so that the energetic width of the packet is inversely proportional to the lifetime of the excited atom.
 

Related to WaveLengths of Light Waves and their respective photons

What is the relationship between wavelength and energy of light waves?

The energy of a photon is directly proportional to its frequency, and since wavelength and frequency are inversely related, the energy of a photon is also inversely proportional to its wavelength. This means that shorter wavelengths have higher energy photons and longer wavelengths have lower energy photons.

How are light waves and their respective photons measured?

Light waves are measured in terms of their wavelength, which is typically measured in nanometers (nm). Photons, on the other hand, are measured in terms of their energy, which is typically measured in electron volts (eV) or joules (J).

What is the electromagnetic spectrum and where do light waves and photons fall on it?

The electromagnetic spectrum is the range of all possible frequencies of electromagnetic radiation. Light waves and their respective photons fall within the visible spectrum, which ranges from approximately 400nm (violet) to 700nm (red). This spectrum also includes other forms of electromagnetic radiation such as radio waves, microwaves, infrared, ultraviolet, X-rays, and gamma rays.

How do light waves and photons interact with matter?

When light waves encounter matter, they can either be transmitted, reflected, absorbed, or scattered. The behavior of photons is determined by their energy and the properties of the matter they interact with. For example, higher energy photons are more likely to be absorbed by matter, while lower energy photons are more likely to be transmitted or scattered.

Can light waves and photons have different colors?

Yes, light waves and photons can have different colors. The color of light is determined by its wavelength, and since different wavelengths correspond to different energies, photons of different colors will have different energies as well. For example, blue light has a shorter wavelength and higher energy compared to red light.

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