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borovecm
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Homework Statement
I have to find volume of tetrahedron that is bounded between 4 planes.
Planes are
x+y+z-1=0
x-y-1=0
x-z-1=0
z-2=0
Homework Equations
[tex]\vec{a}[/tex]=[tex]\vec{AB}[/tex]=(X2-X1)[tex]\vec{i}[/tex]+(y2-y1)[tex]\vec{j}[/tex]+(z2-z1)[tex]\vec{k}[/tex]
[tex]\vec{b}[/tex]=[tex]\vec{AC}[/tex]=(X2-X1)[tex]\vec{i}[/tex]+(y2-y1)[tex]\vec{j}[/tex]+(z2-z1)[tex]\vec{k}[/tex]
[tex]\vec{c}[/tex]=[tex]\vec{AD}[/tex]=(X2-X1)[tex]\vec{i}[/tex]+(y2-y1)[tex]\vec{j}[/tex]+(z2-z1)[tex]\vec{k}[/tex]
V(parallelepiped)=[tex]\vec{a}[/tex][tex]\ast[/tex]([tex]\vec{b}[/tex][tex]\times[/tex][tex]\vec{c}[/tex])
V(tetrahedron)=1/6*V(parallelepiped)
The Attempt at a Solution
I found four points where planes meet. These are:
A(1,0,0)
B(0,-1,2)
C(3,2,2)
D(3,-4,2)
From that I made vectors AB, AC, AD and then I put that into [tex]\vec{a}[/tex][tex]\ast[/tex]([tex]\vec{b}[/tex][tex]\times[/tex][tex]\vec{c}[/tex]) and got that volume of parallelepiped is 4. From there I got that volume of this tetrahedron is 2/3. Is this the correct and shortest way to get a solution? My teacher said that I can use formula V=B*v/3 but I don't know where to use it.
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