Volume of Bubble: Solve for V2 at Depth of 30 m

[mikefitz]

Homework Statement

A bubble with a volume of 1.00 cm3 forms at the bottom of a lake that is 30 m deep. The temperature at the bottom of the lake is 20°C. The bubble rises to the surface where the water temperature is 35°C. Assume that the bubble is small enough that its temperature always matches that of its surroundings. What is the volume of the bubble just before it breaks the surface of the water? Ignore surface tension.

Homework Equations

PV=nRT

P1V1/T1 = P2V2/T2

The Attempt at a Solution

P2 = 1atm
P1 = 1 atm + 1000 * 9.81 * 30 => 3.943atm

3.943atm*1cm3/20C = 1atm*V2/35C
V2=6.9cm3

This value for V2 is way too big, where did I screw up? Thanks

 

[Kurdt]

You've used celcius instead of absolute temperature.

 

[mikefitz]

ahh

so,

3.943/293 = V2/308
V2=4.1448cm3?