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- #1

#### karush

##### Well-known member

- Jan 31, 2012

- 2,928

vol of right circular cone is $$V=\frac{1}{3} \pi r^2 h$$

from this $$h=\frac{3V}{\pi r^2}$$

$$\frac{dh}{dt}=\frac{3}{\pi r}\frac{dV}{dt}$$

$$\frac{\pi r}{3}\frac{dh}{dt}=\frac{dV}{dt}$$

not sure about this we don't have t or rate of change of height

this next question is the same except height is constant

(b) Find the rate of change of the volume with respect to the radius if the height is constant.