# Volume Maximization Problem

#### leprofece

##### Member
A tree trunk is shaped like a truncated cone it has 2 m of length and diameters of their bases are 10 cm and 20 cm. Cut a square straight section so that the axis of the beam coincides with the axis of the truncated cone. find the beam volume maximum that can be drawn from this form.

answer 13,3 cm 13,3 cm y 133 cm

I have no idea maybe the equations are

truncated cone
V = Pir^2H/3

a = piR^2

r= D/2

#### MarkFL

Staff member
Re: max and min 289

I get completely different answers, which leads me to believe I am not interpreting your intentions correctly. Could you provide a diagram? You can draw a crude sketch using a graphics editing program (MS Paint if you run Windows) and upload it as an attachment. Unless we know what the problem is asking, we are at a loss to help you. Help us to help you.

#### leprofece

##### Member
Re: max and min 289

I get completely different answers, which leads me to believe I am not interpreting your intentions correctly. Could you provide a diagram? You can draw a crude sketch using a graphics editing program (MS Paint if you run Windows) and upload it as an attachment. Unless we know what the problem is asking, we are at a loss to help you. Help us to help you.

volume cone truncated=[ (R²+r²+ R.r).¶.H]/ 3, with R=radio major bass
The tree trunk has two circles that are equals
its diaMEters are 10 and 20 cm so radius are 5 and 10
The two axes are equals when I cut the trunk
What is the trunk of max volume
this may be the answer because the books sometimes has mistakes

It is very easy suposse the graph so the book may be it is wrong

#### leprofece

##### Member
volume cone truncated=[ (R²+r²+ R.r).¶.H]/ 3, with R=radio major bass
The tree trunk has two circles that are equals
its diaMEters are 10 and 20 cm so radius are 5 and 10
The two axes are equals when I cut the trunk
What is the trunk of max volume
this may be the answer because the books sometimes has mistakes

It is very easy suposse the graph so the book may be it is wrong

#### MarkFL

Staff member
volume cone truncated=[ (R²+r²+ R.r).¶.H]/ 3, with R=radio major bass
The tree trunk has two circles that are equals
its diaMEters are 10 and 20 cm so radius are 5 and 10
The two axes are equals when I cut the trunk
What is the trunk of max volume