Virial coefficients of the ideal gas equation.

In summary, the conversation discusses the virial expansion and its application in accounting for deviations from the ideal gas law. The first problem involves finding the value of B(T)/(V/n) for different temperatures using the given table of B values for nitrogen at atmospheric pressure. The solution involves manipulating the ideal gas equation and solving for x in a quadratic equation, but this may not be a suitable technique for the problem. The second problem involves finding the second virial coefficient B for a gas obeying the van der Waal's equation in terms of a and b. The solution involves applying the binomial expansion and simplifying the equation to get a final expression for B. There is also a suggestion to approximate B/(V/n) as B/(RT
  • #1
EricVT
166
6

Homework Statement



Even at low density, real gases don't quite obey the ideal gas law. A systematic way to account for deviations from ideal behavior is the virial expansion. Just working with the first order virial expansion we have:

PV=nRT(1 + B(T)/(V/n))

B(T) is a virial coefficient. A table is given with some measured values of B at different temperatures for nitrogen at atmospheric pressure (temp on left, B value on right separated by "/"):

T(K) / B(cm^3/mol)
-------------------
100 / -160
200 / -35
300 / -4.2
400 / 9.0
500 / 16.9
600 / 21.3

The problem asks to find the value of B(T)/(V/n) for each value of T given in the table.

Homework Equations



PV=nRT (ideal gas equation)

The Attempt at a Solution



Since B(T) is given in the table, it seems that only (V/n) needs to be found and then a simple division of terms should yield the answer for each T that you insert into the equation.

First I divided both sides by n and P, and set (V/n)=x, and set the quantity R/P = C

==> x = CT(1+B/x)
==> x/(1+b/x) = CT
==> x^2 = CTx +CTB
==> x^2 - CTx - CTB = 0

This is a quadratic for x, which I solved to get:

x = (1/2)(CT + sqrt[(CT)^2 -4(-CTB)] ==> x = (1/2)(CT + sqrt[(CT)^2 + 4(CTB)]

or x = (1/2)(CT - sqrt[(CT)^2 + 4(CTB)]

However, (CT)^2 is a very small number and for negative B terms such as -160 (the first value in the given table) you can't get real solutions to this quadratic. This doesn't seem correct since these virial terms represent corrections to real intermolecular interactions, so I feel like this technique must not be suitable for this problem.

Is there some misunderstanding on my part about what is being asked? The problem gives B as a function of T alone, but it seems like you can manipulate the ideal gas law to show B as a function of P,V,n, and T. This makes me think there is something I am not understanding about what is given in this problem.

Homework Statement



Another equation of state is given by the van der Waals equation:

(P + a*n^2/V^2)(V - n*b) = n*R*T

where a and b are constants that depend on the type of gas. Calculate the second virial coefficient B for a gas obeying the van der Waal's equation, in terms of a and b.

Homework Equations



Hint: The binomial expansion says that (1 + x)^p ~ 1 + p*x +(1/2)(p)(p-1)(x^2) for |px|<<1. Apply this approximation to the quantity [1-(n*b/V)]^(-1).

The Attempt at a Solution



First of all, is the virial expansion for the van der Waal's equation just

(P + a*n^2/V^2)(V - n*b) = n*R*T(1 + B/(V/n)) like for the ideal gas law virial expansion? I assumed it was and worked from there. I basically just divided out terms until I got

[1-n*b/V]^(-1) = [n*R*T*(1+B/(V/n))]/[P*V+ a*n^2/V)

Then applied the given hinted approximation and followed through all the boring algebra to finally get:

B = [P*V^2 + a*n^2]/[R*T*n^2 + ((R*T*b*n^3)/V)(1+n*b/V)] - V/n

Yikes! Doesn't seem too convincing (the units don't even make sense!), plus I'm not sure if my answer was only supposed to be in terms of "a" and "b" or if the other variables are fine as well.

Any help on this would be appreciated. This looks like a great community, so hopefully I can fit right in.
 
Last edited:
Physics news on Phys.org
  • #2
One thing I've just thought of.

Can we approximate B/(V/n) as B/(RT/P), since this is a first order approximation? That could make the first question a bit easier and avoid the troubles of non-real solutions to the quadratic. But I have to wonder how accurate this approximation would be.
 
  • #3


I would like to first clarify that the virial coefficients are used to account for deviations from ideal gas behavior in the ideal gas equation. These coefficients represent corrections to the ideal gas law, taking into account real intermolecular interactions. In the first problem, the table provides values of the first virial coefficient, B, for nitrogen at different temperatures. The problem asks to find the value of B(T)/(V/n) for each temperature given in the table. This means that we need to find the value of (V/n) for each temperature and then divide it by the corresponding B value to get the desired ratio.

In order to find the value of (V/n), we can use the ideal gas equation PV=nRT. Rearranging this equation, we get (V/n)=RT/P. Substituting this into the expression for B(T)/(V/n), we get B(T)/(V/n)=B(T)*P/(RT). Plugging in the values of P, T, and B from the table, we can find the values of B(T)/(V/n) for each temperature.

In the second problem, we are asked to find the second virial coefficient, B, for a gas obeying the van der Waals equation. The van der Waals equation is given by (P + a*n^2/V^2)(V - n*b) = n*R*T. To find the value of B, we can use the definition of the second virial coefficient, which is given by B = -a*n^2/V^2. Substituting this into the van der Waals equation, we get the expression (P + B*V^2)(V - n*b) = n*R*T. This equation can be solved for B to get the desired expression in terms of a and b.

Regarding the hint given in the problem, it suggests using the binomial expansion to approximate the term [1-(n*b/V)]^(-1). This approximation can be used to simplify the algebra and make the solution easier to obtain. However, it is not necessary to use this approximation to solve the problem. In conclusion, the second virial coefficient for a gas obeying the van der Waals equation can be calculated using the definition of the second virial coefficient and solving the equation for B.
 

Related to Virial coefficients of the ideal gas equation.

What are virial coefficients?

Virial coefficients are parameters used in the ideal gas equation to correct for deviations from ideal gas behavior. They represent the interactions between gas molecules and are used to improve the accuracy of the equation at higher pressures.

How do you calculate virial coefficients?

Virial coefficients are calculated by fitting experimental data to the ideal gas equation and solving for the coefficients. Alternatively, they can be calculated from molecular theory or computer simulations.

Why are virial coefficients important?

Virial coefficients are important because they allow for more accurate predictions of gas behavior at higher pressures. They also provide information about the interactions between gas molecules, which can be useful in understanding the properties of different gases.

What is the significance of the second virial coefficient?

The second virial coefficient is the most commonly used coefficient and represents the attractive interactions between gas molecules. It is important in determining the critical point of a gas and in understanding the stability of gas mixtures.

How do virial coefficients change with temperature and pressure?

Virial coefficients typically decrease with increasing temperature and increase with increasing pressure. However, the exact behavior depends on the specific gas and the interactions between its molecules. Higher order coefficients may also exhibit more complex behavior.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
840
  • Introductory Physics Homework Help
Replies
2
Views
785
  • Introductory Physics Homework Help
Replies
33
Views
1K
  • Introductory Physics Homework Help
Replies
12
Views
825
  • Introductory Physics Homework Help
Replies
3
Views
242
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
994
  • Introductory Physics Homework Help
Replies
10
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
747
  • Introductory Physics Homework Help
Replies
2
Views
2K
Back
Top