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please can i see the graph, and also include explanation so that i can understand better

- Thread starter Jerome
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- Thread starter
- #1

please can i see the graph, and also include explanation so that i can understand better

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- Mar 5, 2012

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please can i see the graph, and also include explanation so that i can understand better

The formula for velocity with uniform acceleration is:i don't have answers to that.

$$v = v_0 + a t$$

where $v$ is the speed at time $t$, $v_0$ is the initial speed, and $a$ is the uniform acceleration.

Is this formula known to you?

Anyway, in your problem, we can deduce that $v_0 = 0$, since the train is initially at rest.

And $a=0.5 m/s^2$ is given.

Do you know how to draw the graph of $v=0.5 t$ for the time period of 0 to 20s?

What will be the speed at $t=20s$?

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Welcome to MHB, Jerome!

The formula for velocity with uniform acceleration is:

$$v = v_0 + a t$$

where $v$ is the speed at time $t$, $v_0$ is the initial speed, and $a$ is the uniform acceleration.

Is this formula known to you?

Anyway, in your problem, we can deduce that $v_0 = 0$, since the train is initially at rest.

And $a=0.5 m/s^2$ is given.

Do you know how to draw the graph of $v=0.5 t$ for the time period of 0 to 20s?

What will be the speed at $t=20s$?

i got that thanks, the graph looks like a trapezium, so the area of the trapezium is the total distance right?

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- #6

- Mar 5, 2012

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Yep!i got that thanks, the graph looks like a trapezium, so the area of the trapezium is the total distance right?