Berean7 said:Homework Statement
A box is hurled up an incline plane of 20 degrees at 10m/second. There is no friction. What is the velocity after 3 seconds. I know gravity and the sin of 20 degrees has to be factored in.
Homework Equations
v=u+at. u is initial velocity, v is velocity after 3 seconds, t is time.
The Attempt at a Solution
9.81x.342=3.355ms^-2. Using the above equation I calculate -.065m/s (10-3.55x3). This does not match any of my answers. I do not know were I went off-track.
The velocity of a box going up an inclined plane can be calculated using the formula: v = √(2gh), where v is the velocity, g is the acceleration due to gravity, and h is the height of the inclined plane.
The steeper the angle of the inclined plane, the faster the box will accelerate and therefore have a higher velocity. This is because the component of gravity acting down the plane increases with a steeper angle.
Yes, the velocity of the box can be zero at the top of the inclined plane if all of its potential energy is converted to kinetic energy. However, it will then start to accelerate back down the plane due to the force of gravity.
Yes, friction will act against the motion of the box and therefore decrease its velocity. The amount of friction will depend on the coefficient of friction between the box and the inclined plane surface.
The mass of the box, the height of the inclined plane, and the acceleration due to gravity can all affect the velocity of the box. Air resistance may also play a role if the box is moving at high speeds.