Velocity in a gravitational field

In summary, the conversation discusses a scenario where a mass is released from infinity and attracted towards a planet of greater mass. The only force acting on the mass is the gravitational force and an expression for the velocity of the mass at a separation distance is derived using the law of conservation of energy. The question also asks if the mass will enter a circular orbit around the planet, which is determined by comparing its velocity to the required velocity for circular motion. The masses never collide and the motion is considered from the viewpoint of a stationary observer.
  • #1
PWiz
695
116

Homework Statement


a) A mass ##m##, initially at rest, is released from infinity, and is attracted towards a planet of mass ##M##, displacing towards it in a direction parallel to the gravitational field lines present between the masses. Assuming that the only force acting on ##m## is the gravitational force of attraction, and provided ##M>m##, find an expression for the velocity ##V_0## of the mass ##m## at a separation distance of ##x## from ##M## in terms of ##G##,##M## and ##x##.
b) Given that the velocity required for an object to be in circular motion at a distance ##r## is given by ##\sqrt{\frac{GM}{r}}##, determine if ##m## will enter a circular orbit around the planet.

Homework Equations


##a=\frac{GM}{r^2}##
##\delta PE = -\delta KE##

The Attempt at a Solution



I tried finding an expression for ##\int_x^∞ a## ## dt## by letting it equal to ##v \frac{dv}{ds}## (since there is no ##t## in the formula for ##a##), but was unable to find an expression for ##\frac{dv}{ds}## as well(s=displacement).

Then I tried using the law of conservation of energy to solve it, and I used the equation ##KE = \frac{GMm}{x} = \frac{1}{2}mv^2## (deriving it from the second relevant equation) and came to the expression ##v = \sqrt{\frac{2GM}{x}}##, but I have my doubts about this.
As to the second part, I'm lost.

Any help is appreciated.
 
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  • #2
Your approach with energy conservation is reasonable. You could in principle use something like the first, but that would amount to essentially the same as solving the differential equation for the scenario and it is much easier to use energy conservation.

For part 2, why don't you just compare the velocities?
 
  • #3
Well here's my deal with this. Your conservation of energy equation uses x as a distance traveled from infinity, which is not necessarily the same as the separation distance of the two masses. Part 2 I think is a trick question. You could possibly end up with a circular orbit if m started with some non zero velocity which was not directed radially toward the center of M, but I just see m and M crashing together.

I agree with orodruin on part 1, I would probably try CoE, but I still need to think about how I would actually approach it. I still think part 2 is a trick question. You need some non radial force acting on m.
 
  • #4
I guess for 2 I just kind of automatically assumed M was not accelerating and was not in relative motion perpendicular to the radial line between the two masses.
 
  • #5
BiGyElLoWhAt said:
Your conservation of energy equation uses x as a distance traveled from infinity, which is not necessarily the same as the separation distance of the two masses
I think the equation was used correctly. The distance traveled from infinity would be infinity.
BiGyElLoWhAt said:
Part 2 I think is a trick question.
I agree.
 
  • #6
The original problem statement says that M > m, not that M >> m. Are we to take it that both masses will be accelerating towards each other? If so, a CoE approach will have to take this into account, and the frame of reference in which Vo "measured" needs to be specified.
 
  • #7
gneill said:
The original problem statement says that M > m, not that M >> m. .
Yes, that bothered me. But then, why mention M > m at all?
 
  • #8
haruspex said:
Yes, that bothered me. But then, why mention M > m at all?
Perhaps to break the symmetry of the problem so one would have to consider a bit more deeply how the KE is to be divided between the masses?
 
  • #9
haruspex said:
Yes, that bothered me. But then, why mention M > m at all?

It bothered me too. I took it as M >> m and tried to be as brief and to the point as possible not to confuse the OP further with the details that arise if you look at what the actual quoted problem was.

I did the same for problem 2, obviously there needs to be a non-zero angular momentum for the masses to have circular orbits and without any non-radial force, the orbit is either a hyperbola, ellipse, or parabola (or as in the case with zero angular momentum, a line). However, the formulation of the problem suggests that you can argue for the non-circularity of the orbit just from the velocity at a given radius (i.e., the circular orbit velocity is lower than the escape velocity by a factor ##\sqrt 2##).
 
  • #10
Thank you all for replying. I'm sorry, I forgot to one thing that was there in the original question: the masses never collide.
Additionally, there was a typo by me - it is ##M>>m## , not ##M>m##. Since this is the case, I believe that the kinetic characteristics of ##M## are supposed to be ignored for this question(please correct me if I'm wrong). There was an accompanying diagram with the question, which I unfortunately do not possesses at this moment. I can, however, provide a description:
##M## was drawn out to be a planet, the separation between ##M## and ##m## was labelled as ##x##, and a vector arrow for ##V_0## was drawn from ##m## that was not pointed straight towards ##M## (it was in the same general direction though, and I can reasonably estimate the angle between the vector and a line joining the centers of the masses to be not more than ##\frac{π}{4}## ##rad##). No other object was drawn other than these two masses. Also, the answer space for part b) had quite a few lines provided (it was for 4 marks), so I think it requires a fair bit of mathematical explanation.
The question provided no further details.
@BiGyElLoWhAt I think you misunderstood something - ##x## is just used to denote the general separation distance between the masses.
@gneill Frames of reference are not specified; I believe the motion of the masses are being considered from the point of a hypothetically stationary observer.

I tried comparing the velocities, and as Orodruin correctly pointed out, their relationship appears to have a factor of ##\sqrt{2}## . If I let the velocities be equal to each other, then ##x=2r## , and I have no idea what this could imply. I still didn't get one thing - is my expression for ##V_0## correct (for part a) )?
 
  • #11
PWiz said:
I tried comparing the velocities, and as Orodruin correctly pointed out, their relationship appears to have a factor of ##\sqrt{2}## . If I let the velocities be equal to each other, then ##x=2r## , and I have no idea what this could imply. I still didn't get one thing - is my expression for ##V_0## correct (for part a) )?

Do not stare yourself blind on letters. Think about what they represent.
 
  • #12
Orodruin said:
Do not stare yourself blind on letters. Think about what they represent.
The velocity of ##m## is never equal to the velocity required to maintain circular motion at any particular distance...?
 
  • #13
I must add that all this is being considered in two dimensions.
 

Related to Velocity in a gravitational field

1. What is velocity in a gravitational field?

Velocity in a gravitational field refers to the speed and direction of an object as it moves under the influence of gravity. This velocity is affected by the mass and distance of the object from the source of gravity.

2. How is velocity in a gravitational field calculated?

Velocity in a gravitational field is calculated using the formula v = √(2GM/r), where v is the velocity, G is the gravitational constant, M is the mass of the object, and r is the distance from the source of gravity.

3. How does velocity change in a gravitational field?

As an object moves in a gravitational field, its velocity changes due to the acceleration caused by gravity. This acceleration is constant and causes the object to increase in velocity as it falls towards the source of gravity.

4. How does velocity in a gravitational field differ from velocity in a vacuum?

In a gravitational field, an object's velocity is affected by the force of gravity, while in a vacuum, an object's velocity is not affected by any external forces. This means that an object will accelerate differently in a gravitational field compared to a vacuum.

5. What is the relationship between mass and velocity in a gravitational field?

The relationship between mass and velocity in a gravitational field is directly proportional. This means that as the mass of an object increases, its velocity will also increase in order to maintain the same gravitational force and acceleration.

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