Sep 24, 2021 #2 P Prove It Well-known member MHB Math Helper Jan 26, 2012 1,470 It might be worth evaluating each line in their vector forms, and then seeing if you can find where they intersect.

It might be worth evaluating each line in their vector forms, and then seeing if you can find where they intersect.

Oct 15, 2021 #4 mrtwhs Active member Oct 15, 2015 46 Although $\dfrac{x}{1} = \dfrac{y}{2} = \dfrac{z}{3}$ is a line, $3\beta^2x+3(1-2\alpha)y+z=3$ is not. It is a plane.

Although $\dfrac{x}{1} = \dfrac{y}{2} = \dfrac{z}{3}$ is a line, $3\beta^2x+3(1-2\alpha)y+z=3$ is not. It is a plane.