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bergausstein
Active member
 Jul 30, 2013
 191
I just don't understand others way solving this problem
to solve for the unknown magnitudes of the two vectors I have to sum up all of the components in x and y and set them equal zero and from there I'll get some systems of equation.
I saw a method where they let the xcomponent of AB and BE to be
$\displaystyle\frac{3}{5}\cdot 9.38$ and $\displaystyle\frac{3}{5}\cdot BE$ respectively.
and the ycomponents of AB and BE to be
$\displaystyle\frac{4}{5}\cdot 9.38$ and $\displaystyle\frac{4}{5}\cdot BE$ respectively
Can you explain why they do that?
and how can we solve this using angle
I know that $\arctan(\frac{4}{3})=53.1\deg$ but I'm uncertain on how to plug it in my equation properly I also know that to get the xcomponent I have to multiply the magnitude of the vector I'm interested into by the $\cos(53.1)$ in the problem given. but this configuration makes me wonder if I'm doing it correctly. hope you can help me with this. thanks!
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