- #1
denian
- 641
- 0
evaluate
[tex]\int_{1}^{2} \frac{x^2 - 2x - 9}{(2x-1)(x^2+3)} dx[/tex]
<br>
i already get theanswer [tex]\searrow -1.09 [/tex]
then, given that
[tex]
y = \frac{x^2 - 2x - 9}{(2x-1)(x^2+3)}
find \frac{dy}{dx} [/tex] when x=-1
how to use the answer from previous stage to apply into this question?
[tex]\int_{1}^{2} \frac{x^2 - 2x - 9}{(2x-1)(x^2+3)} dx[/tex]
<br>
i already get theanswer [tex]\searrow -1.09 [/tex]
then, given that
[tex]
y = \frac{x^2 - 2x - 9}{(2x-1)(x^2+3)}
find \frac{dy}{dx} [/tex] when x=-1
how to use the answer from previous stage to apply into this question?