- #1
jacksonpeeble
Gold Member
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Homework Statement
16. Determine the end behavior of the polynomial P(x)=x3(x+2)(x-3)2.
19. (No Calculator) Sketch the graph of the polynomial function P(x)=2x^3-x^2-18x+9. Where is P(x)>=0?
22. If P(x) has a local maximum at (1,5) and a local minimum at (-2, -4), then find the extrema of f(x)=P(x-2)+3.
Homework Equations
16. P(x)=x3(x+2)(x-3)2
19. P(x)=2x^3-x^2-18x+9
22. f(x)=P(x-2)+3
The Attempt at a Solution
16. Degree=3, Lead Coefficient=+, therefore [tex]y\rightarrow\infty[/tex] as [tex] x\rightarrow\infty[/tex] and [tex]y\rightarrow-\infty[/tex] as [tex]x\rightarrow-\infty[/tex]. The answer key (which we have, so I don't just need the final answer) says I'm wrong.
19. The degree is odd, and the leading coefficient is positive, so the end behavior is [tex]y\rightarrow\infty[/tex] as [tex] x\rightarrow\infty[/tex] and [tex]y\rightarrow-\infty[/tex] as [tex]x\rightarrow-\infty[/tex]. The +9 no doubt moves it up nine. However, what other information do I need to include to accurately sketch the graph, and how do I determine where P(x) is greater than or equal to zero?
22. What? Where did the f(x) come from? How does this work (utterly perplexed)?