Variation of Monty Hall problem

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There are three envelopes. One contains $50. Another contains $100. The third contains $500. You pick one but it is not opened. If the host reveals one of the other two and it contains $50 or $100 (both considered as goats), the answer is to switch as in Monty hall case. However, if he reveals one with $500, you are now left with either picking one with $50 or $100. Do you switch your choice to the other unopened one? (This was an interview question for a fund manager post)
 
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It depends how Monty decides which envelope to open.
 
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  • #3
coolkatmeow said:
There are three envelopes. One contains $50. Another contains $100. The third contains $500. You pick one but it is not opened. If the host reveals one of the other two and it contains $50 or $100 (both considered as goats), the answer is to switch as in Monty hall case. However, if he reveals one with $500, you are now left with either picking one with $50 or $100. Do you switch your choice to the other unopened one? (This was an interview question for a fund manager post)
If Monty can reveal the top prize, then we may assume he is opening an envelope at random and this is the so-called Monty Fall problem. In all cases, it makes no difference whether you switch or not.

The Monty Hall problem requires that Monty knows where the car is and never reveals it. Or, in this case, never reveals the $500.
 
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coolkatmeow said:
if he reveals one with $500, you are now left with either picking one with $50 or $100. Do you switch your choice to the other unopened one?
I am not sure I would even call this a variant of the Monty Hall problem. In that one he never showed the top prize, and thus he provided information to the player. Here, since Monty sometimes shows the top prize then that really removes the crux of the scenario.
 
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  • #5
PeroK said:
If Monty can reveal the top prize, then we may assume he is opening an envelope at random and this is the so-called Monty Fall problem. In all cases, it makes no difference whether you switch or not.

The Monty Hall problem requires that Monty knows where the car is and never reveals it. Or, in this case, never reveals the $500.
Seems like the Monty fall problem is similar to reducing the Monty hall paradox to a two envelopes puzzle (watch YouTube)...yes, in this case the host is just like a second player who does not know where the top prize is, but this second player only have 2 choices to make whereas the first player has 3 options. It's like the first manager has to decide whether the financial market will go up, down or remain flat whereas the second manager just bet that first manager is wrong and choose between the remaining 2 outcomes.
 
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  • #6
PeroK said:
It depends how Monty decides which envelope to open.
You are exactly right. This is the tricky part because the player or audience does not know whether the host knows where is what and thus observing him revealing any envelope does not affect the probability of the outcome.
If the host already know where is what, then he knows the player made the right first choice or not, but he may intentionally open a goat from the other two doors to mislead the player who thinks the host is giving information to switch choice.

Thanks for all the replies.
 
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  • #7
I think the best answer for the interview would be to get, say ten players and have them each make their own, independent choices. Then take the track record of the winner and market it, with a 2&20 fee schedule, as an uncorrelated source of alpha
 
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1. What is the Monty Hall problem?

The Monty Hall problem is a probability puzzle based on a game show scenario. Imagine you're on a game show and given the choice of three doors: behind one door is a car, and behind the other two, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. You're then given a choice: stick with your original pick or switch to the remaining unopened door. The question is, should you switch to maximize your chances of winning the car?

2. What is the variation of the Monty Hall problem?

The variations of the Monty Hall problem typically involve changes to the number of doors, the behavior of the host, or the rules regarding the revealing of what's behind the doors. For example, a variation might include more than three doors, or scenarios where the host might open a door revealing a car, or where the host chooses randomly whether to offer a switch.

3. Does the probability of winning change in the variations?

Yes, the probability of winning can change based on the variations of the rules. For instance, if the number of doors increases, and the host still reveals a goat after the initial choice, the advantage of switching generally increases. The specific probabilities depend on the number of doors and the particular rules about how the host behaves and what information is revealed.

4. What is the optimal strategy in the variations of the Monty Hall problem?

The optimal strategy can vary depending on the specific rules of the variation. However, in many cases, especially where the host's actions after the initial choice are similar to the original game (revealing a goat and offering a switch), the strategy of switching doors often remains advantageous. Analyzing the specific situation and understanding the probability changes with different actions is crucial to determining the best strategy.

5. How does the player's initial choice affect the outcome in the variations?

In most variations, the initial choice of the player typically results in a lower probability of winning the car compared to the probability after the host reveals additional information (usually showing a goat). This is because the initial choice is made when all doors are still options, thus having a lower chance of selecting the car. Once the host reveals more information, recalculating the probabilities often shows a benefit to switching, similar to the original problem.

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