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PART A

3) Solve 2x^2 + 4x = 15 by using the quadratic formula.

x = -1 +/- 2sqr34

4) Determine whether the given pairs of lines are parallel, perpendicular, or neither.

a) y = -4x + 3 b) x - 4y = 4

My answer: Perpendicular

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PART A

3) Solve 2x^2 + 4x = 15 by using the quadratic formula.

x = -1 +/- 2sqr34

4) Determine whether the given pairs of lines are parallel, perpendicular, or neither.

a) y = -4x + 3 b) x - 4y = 4

My answer: Perpendicular

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3.) Incorrect.

We have:

\(\displaystyle 2x^2+4x-15=0\)

\(\displaystyle x=\frac{-4\pm\sqrt{(4)^2-4(2)(-15)}}{2(2)}=\frac{-4\pm\sqrt{136}}{4}=\frac{-4\pm2\sqrt{34}}{4}=\frac{-2\pm\sqrt{34}}{2}\)

We could choose to write this as:

\(\displaystyle x=-1\pm\sqrt{\frac{17}{2}}\)

4.)

a) Correct. The product of the slopes of the two lines is -1.

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