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- #1

I want to use the volume of revolution around the y-axis

we have the line

[tex]y - 0 = \dfrac{h}{r-R} (x - R)[/tex]

[tex] x = \frac{r-R}{h} y +R [/tex]

The volume will be

[tex] \pi \int_{0}^{h} \left(\frac{r-R}{h} y + R\right)^2 dy [/tex]

[tex]\pi \int_{0}^{h} \frac{(r-R)^2y^2}{h^2} + \frac{2R(r-R)y}{h} + R^2 dy [/tex]

now i just have to evaluate the integral, did i miss something ?