- #1
Kingfisher1
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I have been asked to determine the length of time the ball will be in the air. I understand the basic concept, but the execution is tripping me up. It has been years since I have done a math course, and this is my first foray into physics, so I am a bit rusty. :)
A ball is thrown upwards at a 15 degree angle. Initial velocity is 20m/s. In a previous questions V1(vertical) was determined to be 5.2 m/s. Acceleration is of course -9.81 m/s^2.
Equation used:
d= v1(t) + 1/2(a)(t)^2
d= 0
a=-9.8 m/s ^2
V1(vert)= 5.2 m/s
t= X
My efforts:
0=(5.2)t + 1/2 (-9.8)t
0= t (5.2 - 4.9)
t=0
So two issues here:
1) I am truly at a loss when re-arranging this equation, I shuffled things around but am not sure it was correct, refresh my memory please!
2) My text states that I should have two answers. I don't understand how I am to get two answers, as they do not suggest I change the equation in anyway.
Thank you for helping!
A ball is thrown upwards at a 15 degree angle. Initial velocity is 20m/s. In a previous questions V1(vertical) was determined to be 5.2 m/s. Acceleration is of course -9.81 m/s^2.
Equation used:
d= v1(t) + 1/2(a)(t)^2
d= 0
a=-9.8 m/s ^2
V1(vert)= 5.2 m/s
t= X
My efforts:
0=(5.2)t + 1/2 (-9.8)t
0= t (5.2 - 4.9)
t=0
So two issues here:
1) I am truly at a loss when re-arranging this equation, I shuffled things around but am not sure it was correct, refresh my memory please!
2) My text states that I should have two answers. I don't understand how I am to get two answers, as they do not suggest I change the equation in anyway.
Thank you for helping!