- #1
repugno
- 78
- 0
2^(-log2(x)) It reads, 2 to the power of -log base2 x
The problem is that I don't understand why this can also be written as x^-1
For some reason the base and the log2 cancel out. Can anyone explain to me why this happens, please?
1/2^(log2(x)) = 1/x
The problem is that I don't understand why this can also be written as x^-1
For some reason the base and the log2 cancel out. Can anyone explain to me why this happens, please?
1/2^(log2(x)) = 1/x