Understanding Work and Energy: A Short Guide

In summary: Thanks for the help, Haruspex. In summary, the conversation discusses concepts of work and energy, specifically focusing on speed, potential energy, kinetic energy, and acceleration. The conversation also addresses the difference between velocity and speed, the effects of gravity, and the impact of circular motion. Overall, the conversation provides a deeper understanding of these concepts and their application in problem-solving.
  • #1
idllotsaroms
26
0

Homework Statement



http://postimage.org/image/sezpli4pv/
Having some difficulty understanding some concepts of Work and Energy.

Homework Equations



W = F * D
KE = 1/2 mv^2
PE = mgh

The Attempt at a Solution



A) Speed is at B is less than the speed at D, because B has more PE than D
B) False, because there is the force of gravity acting always
C) True, Same location in respect to the graph
D) Less, because force of gravity < 0
E) Less, because B has more PE than H
F) Less, acceleration due to gravity
 
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  • #2
idllotsaroms said:
A) Speed is at B is less than the speed at D, because B has more PE than D
Looks to me that D is slightly higher than B. Are you saying B is higher? But it's such a small difference I wonder if they're meant to be the same height. (I think you looked at the wrong two points.)
B) False, because there is the force of gravity acting always
Acceleration is the result of the net force. If you're standing still, gravity is acting on you but it's countered by the floor, so you don't accelerate. But your answer is right for a different reason. What is happening to the velocity at B?
C) True, Same location in respect to the graph
At (A) above you said it was faster at D. But anyway, this question is asking about velocity, not speed. There's a difference - what is it?
D) Less, because force of gravity < 0
Same misunderstanding as your answer (B).
E) Less, because B has more PE than H
Yes.
F) Less, acceleration due to gravity
It's asking about acceleration in the x direction.
 
  • #3
looks to me that d is slightly higher than b. Are you saying b is higher? But it's such a small difference i wonder if they're meant to be the same height. (i think you looked at the wrong two points.)
Yes, sorry they are on the same level, so speed at B is equal to the speed at D

Acceleration is the result of the net force. If you're standing still, gravity is acting on you but it's countered by the floor, so you don't accelerate. But your answer is right for a different reason. What is happening to the velocity at B?
Is it because the bead is moving in a circular motion at that point (semi circle)?

At (A) above you said it was faster at D. But anyway, this question is asking about velocity, not speed. There's a difference - what is it?
Since they are at the same level, they have the same potential energy, the same kinetic energy, and therefore the same speed So, the velocity at B is equal to D.

Same misunderstanding as your answer (B).
At this point would acceleration be greater than 0 because the dip is a semi-circle with centripetal force aimed towards the middle?

It's asking about acceleration in the x direction.
Sorry!, the acceleration in the X-direction at H would be equal to zero then, because there is no external horizontal force.

A) Speed is at B is equal to the speed at D, because they are at the same height
B) False, because there is some circular motion downward which is less than 0
C) False, because of directionality (different directions)
D) Greater than, because centripetal force towards the center which in this case is upward (+)
E) Less, because B has more PE than H
F) Equal to 0, because there are no external forces acting in the horizontal plane.
 
  • #4
idllotsaroms said:
Yes, sorry they are on the same level, so speed at B is equal to the speed at D
Yes.
Is it because the bead is moving in a circular motion at that point (semi circle)?
Yes. The direction of movement is changing from up to down, so there's a downward acceleration.
Since they are at the same level, they have the same potential energy, the same kinetic energy, and therefore the same speed So, the velocity at B is equal to D.
No. Velocity is a vector. Speed is just its magnitude; it also has direction. If the direction is different the velocity is different.
At this point would acceleration be greater than 0 because the dip is a semi-circle with centripetal force aimed towards the middle?
Yes.
the acceleration in the X-direction at H would be equal to zero then, because there is no external horizontal force.
Yes.
 
  • #5
Thank you for the help Haruspex, I appreciate it!
 

Related to Understanding Work and Energy: A Short Guide

What is the "Bead Sliding from Rest" experiment?

The "Bead Sliding from Rest" experiment is a simple physics experiment in which a bead is placed on a horizontal surface and released from rest. The goal of the experiment is to observe and measure the motion of the bead as it slides down the surface.

What factors affect the motion of the bead in this experiment?

The motion of the bead in this experiment is affected by several factors, including the slope of the surface, the mass of the bead, the coefficient of friction between the bead and the surface, and the presence of any external forces or obstacles.

How can the motion of the bead be described mathematically?

The motion of the bead can be described using the equations of motion, such as the position, velocity, and acceleration equations. These equations take into account the initial conditions of the bead and the forces acting on it.

What is the significance of this experiment in the field of physics?

The "Bead Sliding from Rest" experiment is a fundamental experiment in the study of motion and mechanics. It allows for the application of Newton's laws of motion and the principles of energy and momentum conservation. It also serves as a basis for more complex experiments and real-world applications.

How can this experiment be modified or extended for further study?

This experiment can be modified by changing the initial conditions, such as the starting position or velocity of the bead, or by altering the surface or adding external forces. It can also be extended by introducing more advanced concepts, such as air resistance or non-uniform surfaces, and by using more sophisticated equipment for data collection and analysis.

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