Understanding the Units of Permittivity of Free Space in Coulomb's Law

[wasi-uz-zaman]

Hi please tell me physical significance of permittivity of free space, how can we explain its value having unit of F/m

 

[Svein]

Creating a capacitor with "free space" as the dielectric (or any sort of dielectric), the capacitance is proportional with the permittivity, the area (m²) and inverse proportional with the distance between the plates (m). Therefore, to calculate the capacitance, you multiply with the area and divide by the distance - and you end up with the capacitance (in F).

 

[NascentOxygen]

In a parallel plate capacitor, lines of flux reach across the void to terminate on charges of opposite sign on the opposing plate.
Svein has ably demonstrated the units of ##\epsilon## based on the formula for capacitance, ##C=\epsilon\frac{A}{d}##

The units of ##\epsilon## are not so obvious if you try deconstructing this speed of light formula, ##c=\dfrac 1{\sqrt{\epsilon\mu}}##

 

[helter skelter]

Changing the topic,in coulumbs law
1\4 pi epselon = 9x10^9 but on solving I'm not getting the same

 

[NascentOxygen]

Changing the topic,in coulumbs law
1\4 pi epselon = 9x10^9 but on solving I'm not getting the same

If this is a new topic, you need to start a new thread.

If this is still on the units of permittivity, explain what it is you are trying to solve.

I doubt the formula could be 1\4 pi epsilon. It is almost surely 1/(4 pi epsilon).