It is pointing toward the center of curvature of the trajectory of the vehicle.marlasca23 said:The horizontal component of Normal force, N·sinθ, is not even ponting towards the centre of the curvature.
Because the vertical component is canceled by gravity.marlasca23 said:Why during a banked curve is the horizontal component of the normal force considered as the net force and the centripetal force?
jbriggs444 said:It is pointing toward the center of curvature of the trajectory of the vehicle.
marlasca23 said:Sorry, I don't understand that. Could you explain it more in depth, please?
A.T. said:
The horizontal component of normal force in banked curves is the force exerted by the surface of the banked curve on an object moving along the surface. It is perpendicular to the surface and acts as a support force to keep the object from sliding down the banked curve.
The angle of the banked curve affects the horizontal component of normal force by changing the magnitude of the force. As the angle of the banked curve increases, the horizontal component of normal force also increases, providing more support to the object.
The horizontal component of normal force is directly proportional to the speed of the object. As the speed increases, the force also increases to keep the object from sliding off the banked curve.
The mass of an object has no effect on the horizontal component of normal force in a banked curve. The force is solely dependent on the speed and angle of the banked curve.
Yes, the horizontal component of normal force can be greater than the weight of an object. This can happen when the angle of the banked curve is steep enough and the speed of the object is high enough to create a larger normal force to keep the object from sliding down the banked curve.