Understanding Poisson's Ratio and Restrained Cylinders

In summary, the conversation discusses the concept of Poisson's ratio, which is a material property that describes the ratio of lateral to longitudinal strains. The conversation specifically mentions a scenario where a cylinder made of steel is constrained in the vertical direction and subjected to internal pressure, leading to lateral expansion. The conversation also raises questions about how loading conditions may affect Poisson's ratio and whether it can change for different materials. The expert notes that, in general, loading conditions will not change material properties, including Poisson's ratio, unless dealing with exotic materials.
  • #1
Gaunt
3
0
Hey. I have a couple of questions about Poisson's ratio I hope you guys can answer.

If I have a cylinder made of, let's say steel. Steel has a Poisson's ratio of roughly 0.33. The cylinder is restrained in the vertical direction so no displacement can occur.

If I apply an internal pressure to the cylinder, it is going to expand laterally, but it can't in the vertical direction because it is restrained.

Seeing as the Poisson ratio is a ratio of lateral to longitudinal strains and the strain in the longitudinal direction will be zero, where does that leave the poisson ratio? If The longitudinal strain is zero, you cannot divide the lateral strain by zero!

Am I missing something?
 
Physics news on Phys.org
  • #2
Poissons ratio is a material property. Constraining the movement of a material does nothing to affect that,

In effect by constraining the ends, you are applying a load in tension to counter act the way the material would want to move if it were unconstrained. As you have two loads instead of one on the material very basic calculations will break down as you have combined loads.
 
  • #3
Thanks for the quick reply.

So what you are saying is that regardless of loading conditions a material will always have the same poisson ratio?

Also, the ratio of strains in a loading situation as above wouldn't be Poisson's ratio then, would it?
 
  • #4
Gaunt said:
Thanks for the quick reply.

So what you are saying is that regardless of loading conditions a material will always have the same poisson ratio?

Also, the ratio of strains in a loading situation as above wouldn't be Poisson's ratio then, would it?

This could open a can of worms depending on how detailed we get. As exotic materials can change properties, or even have negative poissons ratios.

In general for 'normal' materials loaded in the elastic range then yes. Loading conditions will not change material properties.
 
  • #5


Hello there, thank you for your questions about Poisson's ratio and restrained cylinders. Let me try to clarify some of your points.

Firstly, you are correct in understanding that Poisson's ratio is a ratio of lateral to longitudinal strains. In the case of your restrained cylinder, the longitudinal strain is indeed zero because it is constrained in that direction. However, this does not mean that the Poisson's ratio is undefined. Rather, it means that the lateral strain will be equal to zero as well, since the cylinder cannot expand laterally due to the constraint. Therefore, the Poisson's ratio in this case would still be 0.33, as it is a material property of steel and does not change based on the boundary conditions.

To further explain, Poisson's ratio is a measure of a material's resistance to lateral deformation when subjected to a longitudinal strain. In your example, the cylinder is experiencing a longitudinal strain due to the internal pressure, but since it is restrained in that direction, it cannot deform laterally. This does not change the fact that the material still has a Poisson's ratio of 0.33, which is a measure of its overall tendency to deform laterally when subjected to a longitudinal strain.

I hope this helps to clarify your understanding of Poisson's ratio and its application in the case of restrained cylinders. Please let me know if you have any further questions. Thank you.
 

Related to Understanding Poisson's Ratio and Restrained Cylinders

1. What is Poisson's ratio?

Poisson's ratio is a material property that describes the ratio of lateral strain to axial strain when a material is under stress. It is denoted by the Greek letter ν (nu) and is typically expressed as a decimal or fraction between -1 and 0.5.

2. How is Poisson's ratio calculated?

Poisson's ratio is calculated by dividing the lateral strain by the axial strain. It can also be calculated by dividing the negative transverse strain by the positive axial strain. Alternatively, it can be calculated using different methods depending on the type of material and the type of stress being applied.

3. What is the significance of Poisson's ratio?

Poisson's ratio is important because it relates to the stiffness and deformation of a material when it is under stress. Materials with a higher Poisson's ratio are more likely to deform laterally when compressed, while materials with a lower Poisson's ratio are more resistant to lateral deformation.

4. How does Poisson's ratio apply to restrained cylinders?

In the context of restrained cylinders, Poisson's ratio refers to the ratio of the transverse strain to the axial strain of a cylinder when it is under stress. This is an important factor to consider in engineering and construction, as it can affect the stability and performance of structures such as pipes and columns.

5. What are some practical applications of understanding Poisson's ratio and restrained cylinders?

Understanding Poisson's ratio and restrained cylinders is crucial in various fields of engineering, such as civil engineering, mechanical engineering, and materials science. It is used in the design and analysis of structures, pipes, and columns, as well as in the manufacturing of materials with specific properties. Additionally, it is important in geology and seismology for understanding the behavior of rocks under stress and predicting earthquakes.

Similar threads

  • Other Physics Topics
Replies
1
Views
985
  • Engineering and Comp Sci Homework Help
Replies
1
Views
1K
  • Mechanical Engineering
Replies
7
Views
2K
  • Classical Physics
Replies
2
Views
2K
Replies
2
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
2
Views
4K
Replies
4
Views
1K
  • Mechanical Engineering
Replies
3
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
12
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
6
Views
12K
Back
Top