Understanding Newtonian Gravitation

In summary, the net force of gravity on a point mass in an enclosed spherical shell is zero, similar to electricity in a Faraday cage. However, if the point mass is placed inside a ring of mass and uniform density, the net force of gravity will still be zero. This is because the masses on the ring are distributed symmetrically, resulting in the cancellation of forces on the point mass. This applies to both spherical shells and annuli.
  • #1
Quantumsatire
10
0
So for a point mass in an enclosed shell, the net force of gravity is zero (similar to electricity in a Faraday cage I presume). However, what happens when that point mass is placed in side the ring of mass m and uniform density. Say the outer shell has radius r and inner shell has radius x, so the region r-x is a massed shell/ring. How would you find the net force of gravity?
 
Physics news on Phys.org
  • #2
If the outer shell alone gives you a net force of zero, then it can be ignored.

You only consider the inner shell and calculate your force in the normal way.
 
  • #3
Quantumsatire said:
So for a point mass in an enclosed shell, the net force of gravity is zero (similar to electricity in a Faraday cage I presume). However, what happens when that point mass is placed in side the ring of mass m and uniform density. Say the outer shell has radius r and inner shell has radius x, so the region r-x is a massed shell/ring. How would you find the net force of gravity?

Net gravitational force on point mass by ring will be always zero. Consider the entire mass of ring as small point equal masses. For every point mass on ring, there will be another point mass symmetrically opposite on the ring. Net force by two opposite masses on the point mass inside cancel out. Thus, net gravitational force is zero
 
  • #4
Quantumsatire said:
So for a point mass in an enclosed shell, the net force of gravity is zero (similar to electricity in a Faraday cage I presume). However, what happens when that point mass is placed in side the ring of mass m and uniform density. Say the outer shell has radius r and inner shell has radius x, so the region r-x is a massed shell/ring. How would you find the net force of gravity?

Do you mean spherical shell or an annulus? They are not the same and the shell theorem only applies to a spherical shell.
 
  • #5


I would like to clarify that there are some inaccuracies in the content provided. Firstly, the concept of Newtonian gravitation applies to all objects with mass, not just point masses. Additionally, the concept of a Faraday cage is related to the behavior of electric fields, not gravitational fields.

To answer the question at hand, the net force of gravity on a point mass placed inside a ring of mass with uniform density can be calculated using the principle of superposition. This means that we can break down the ring into smaller, infinitesimal masses and calculate the individual gravitational forces between the point mass and each infinitesimal mass. These forces can then be vectorially added to find the net force of gravity on the point mass.

The calculation for the net force of gravity would involve integrating the gravitational force equation, which takes into account the masses, distances, and the universal gravitational constant. The result would depend on the specific values of the masses and radii involved in the problem.

It is important to note that the net force of gravity on the point mass would not be zero in this scenario, as there are multiple masses present and their gravitational forces would not cancel out completely. This is in contrast to the situation described in the first part of the content, where the net force of gravity would indeed be zero due to the symmetry of the enclosed shell.

In summary, the net force of gravity on a point mass placed inside a ring of mass with uniform density can be calculated using the principle of superposition and the gravitational force equation. This concept is fundamental to our understanding of Newtonian gravitation and is applicable to a wide range of scenarios in physics.
 

Related to Understanding Newtonian Gravitation

1. What is Newtonian gravitation?

Newtonian gravitation is a theory proposed by Sir Isaac Newton in the 17th century to explain the force of gravity between objects. It states that every object with mass exerts a force on all other objects with mass, and this force is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

2. How does Newtonian gravitation differ from Einstein's theory of relativity?

Newtonian gravitation is a classical theory that only works for objects moving at non-relativistic speeds. Einstein's theory of relativity, on the other hand, is a more modern and accurate theory that takes into account the effects of gravity on objects moving at high speeds or in strong gravitational fields.

3. What is the equation for calculating the force of gravity between two objects?

The equation for calculating the force of gravity between two objects is F = G * (m1 * m2)/r^2, where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

4. Can Newtonian gravitation be used to explain the motion of planets and other celestial bodies?

Yes, Newtonian gravitation is commonly used to explain the motion of planets, moons, and other celestial bodies in our solar system. However, it is not accurate for objects in extreme gravitational fields, such as near black holes.

5. What are some practical applications of Newtonian gravitation?

Newtonian gravitation has many practical applications, such as predicting the trajectories of objects like satellites and spacecraft, calculating the force required to launch a rocket into orbit, and understanding the motion of objects in our solar system. It also plays a crucial role in engineering and designing structures that can withstand the force of gravity.

Similar threads

Replies
6
Views
966
  • Classical Physics
Replies
16
Views
874
Replies
7
Views
2K
Replies
3
Views
1K
Replies
1
Views
1K
Replies
19
Views
888
Replies
2
Views
1K
  • Special and General Relativity
Replies
3
Views
243
  • Special and General Relativity
Replies
6
Views
684
Replies
1
Views
935
Back
Top