Understanding Leibniz's Rule: Use, Why & Examples

  • Thread starter glebovg
  • Start date
In summary: When would one use it and why?The Leibniz rule is a handy tool to have in yourmath toolbox, and you can use it for a variety of different purposes. For example, you can use it to solve convolution integrals, differentiate power series, and more. It can be useful in a variety of different situations, so it's a good idea to have it on hand whenever you need it.In summary, the Leibniz rule is a handy tool that can be used to solve convolution integrals, differentiate power series, and more.
  • #1
glebovg
164
1
Can anyone explain Leibniz's rule?

When would one use it and why?

Examples?
 
Physics news on Phys.org
  • #2
Which Leibniz rule? How to differentiate a definite integral when the variable appears as limit of integration? How to differentiate the nth power of a product of functions?
 
  • #3
Leibniz integral rule.
 
  • #4
You might find a forum member with a pent-up enthusiasm for explaining the Leibniz integral rule. Failing at that, I suggest you ask a more specific question. After all, there are all sorts of treatments of the Leibniz integral rule on the web. What answers one persons "why?" may not satisify another. What do you want to see? a physics problem that uses it? the usual calculus of variations stuff? how to work tricky integrals with it?
 
  • #5
glebovg said:
When would one use it and why?

Examples?

Oh man like all the time in math just doing regular stuff. Just a few days ago I ran into this real-life problem:

If:

[tex]k\int_c^d \frac{e^{b\sqrt{s^2-a^2}}}{\sqrt{s^2-s^2}}e^{sx}ds=I_0(a \sqrt{x^2-b^2})[/tex]

then find:

[tex]k\int_c^d e^{b\sqrt{s^2-a^2}}e^{sx}ds[/tex]

Now, look up Leibniz rule, then differentiate the first expression with respect to b, and find the solution to the second integral.
 
Last edited:
  • #6
glebovg said:
Can anyone explain Leibniz's rule?

When would one use it and why?

Examples?

The other day, I was reading a paper that claimed that

[tex]x(t)=x(0) \exp (at)+b\int_0^t \exp(a(t-\tau))\; u(\tau) d\tau[/tex]

was a solution to

[tex]{{dx(t)}\over{dt}}=a\; x(t)+b\; u(t)[/tex]

I wanted to quickly verify this and used the integral rule to check it. I also double checked it with a Laplace transform method, just for practice, but that's not relevant here.

The integral here is a convolution integral, and differentiating a convolution integral is one example where the rule comes in handy. Note that the derivative with respect to t can not just be moved into the integral without additional modifications because the upper limit depends on t. The Leibniz rule, let's you write the answer correctly and quickly. It does this by adding terms that depend on the derivatives of the limits.
 
Last edited:

Related to Understanding Leibniz's Rule: Use, Why & Examples

1. What is Leibniz's rule and why is it important in mathematics?

Leibniz's rule, also known as the product rule, is a mathematical rule used to find the derivative of a function that is a product of two other functions. It states that the derivative of a product of two functions is equal to the product of the first function's derivative and the second function, plus the product of the first function and the derivative of the second function. This rule is important in mathematics because it allows us to find the derivative of more complex functions, making it a valuable tool in calculus and other branches of mathematics.

2. How is Leibniz's rule used in real-world applications?

Leibniz's rule has many practical applications in fields such as physics, engineering, and economics. For example, in physics, the rule is used to find the rate of change of a quantity over time, such as velocity or acceleration. In economics, it can be used to find the marginal cost or revenue of a product. Overall, Leibniz's rule is a powerful tool for solving real-world problems that involve rates of change.

3. What are some common mistakes when using Leibniz's rule?

One common mistake when using Leibniz's rule is forgetting to apply the rule correctly. This can happen if the product of the functions is not written in the correct form, or if the derivative of one of the functions is not calculated properly. It is important to carefully follow the steps of the rule to avoid making errors. Another common mistake is forgetting to simplify the final answer, which can lead to incorrect results.

4. Can Leibniz's rule be used for functions with more than two factors?

Yes, Leibniz's rule can be extended to functions with more than two factors. This is known as the generalized product rule, and it states that the derivative of a product of n functions is equal to the sum of all possible products of the derivatives of these functions. However, this can become quite complex and is usually only used in more advanced mathematical applications.

5. Can you provide an example of how Leibniz's rule is used to find the derivative of a function?

Sure, let's say we have the function f(x) = (x^2 + 3x)(cosx). To find the derivative of this function, we can use Leibniz's rule, which states that the derivative of a product of two functions is equal to the product of the first function's derivative and the second function, plus the product of the first function and the derivative of the second function. Applying this rule, we get f'(x) = (2x + 3)(cosx) + (x^2 + 3x)(-sinx) = 2xcosx + 3cosx - x^2sinx - 3xsinx.

Similar threads

Replies
9
Views
5K
Replies
4
Views
1K
  • Calculus
Replies
1
Views
1K
Replies
12
Views
2K
Replies
5
Views
2K
Replies
46
Views
2K
  • Calculus
Replies
2
Views
1K
  • Calculus and Beyond Homework Help
Replies
4
Views
1K
Replies
6
Views
2K
Back
Top