- #1
Eitan Levy
- 259
- 11
Homework Statement
First, we connect a capacitor to a voltage source with an electric force of 60V.
After that we put another capacitor with a capacity of 0.01nF instead of the voltage source. As a result, the voltage on the first capacitor is down to 40V.
1. What is the voltage on the second capacitor?
2. What is the capacity of the first capacitor?
Homework Equations
The Attempt at a Solution
This is a very new topic for me. Why the voltage on the second capacitor is 40V and not 20V and how can we calculate the capacity? (Maybe it's 40V because of Kirchhoff's voltage law?)
Thanks in advance.