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#### NecroWinter

##### New member

- Feb 19, 2012

- 3

integrate from 0 to pi/2

the way I tried this is by making u = sin, and then working with du to make cos cancel out

the next thing I did was check my new intervals by plugging in pi/2 and 0 into the u function (becomes 0 to 1)

next, I took the anti derivative of u, which came to (u^3)/3

((u^3)/3))-((u^3)/3)

sin0=0

sin pi/2 = 1

(0^3)/3 - (1^3)/3 = -1/3

except, wolfram alpha gives me 1/3.

What happened?