- #1
Gabriel Maia
- 72
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Hi. I'm reading a solution to a problem concerning a gas of photons. In the solution, the energy of the gas is given as
[itex]E=2\sum_{\vec{k}} \frac{\displaystyle \epsilon_{\vec{k}}}{\displaystyle \exp[\beta\epsilon_{\vec{k}}]+1}[/itex]
where [itex]\epsilon_{\vec{k}}[/itex] is one photon's energy. It is said then that in the thermodynamic limit we have
[itex]\sum_{\vec{k}} \rightarrow \frac{\displaystyle V}{\displaystyle (2\pi)}\int_{0}^{\infty}\,4\pi\,k^{2}dk[/itex]Could you explain how is this change from the summation to the integral is done?
Thank you very much.
[itex]E=2\sum_{\vec{k}} \frac{\displaystyle \epsilon_{\vec{k}}}{\displaystyle \exp[\beta\epsilon_{\vec{k}}]+1}[/itex]
where [itex]\epsilon_{\vec{k}}[/itex] is one photon's energy. It is said then that in the thermodynamic limit we have
[itex]\sum_{\vec{k}} \rightarrow \frac{\displaystyle V}{\displaystyle (2\pi)}\int_{0}^{\infty}\,4\pi\,k^{2}dk[/itex]Could you explain how is this change from the summation to the integral is done?
Thank you very much.