- #1
Taturana
- 108
- 0
[tex]\operatorname{div}\,\mathbf{F}(p) =
\lim_{V \rightarrow \{p\}}
\iint_{S(V)} {\mathbf{F}\cdot\mathbf{n} \over |V| } \; dS[/tex]
This is the definition of divergence from wikipedia...
The divergence is property of a point in space. Is that right?
If the divergence is zero at a point, that means that such point does not contribute with the field as source nor a sink. Is that right?
So, the divergence of a point measures how that point contributes as a source or a sink with the field?
The surface integral in the equation above means a certain area, right? Is that area the area of the entire surface (like a gaussian surface in the gauss's law) or the area of the micro-surface that is "around" the point I'm measuring the divergence on?
Usually I like to think in the dimensions of the conceps (units). I noticed that the unit of divergence will always be area/volume (m^-1). Does that have any meaning?
If someone can help me with some of these questions I would be grateful...
Thank you,
Rafael Andreatta
\lim_{V \rightarrow \{p\}}
\iint_{S(V)} {\mathbf{F}\cdot\mathbf{n} \over |V| } \; dS[/tex]
This is the definition of divergence from wikipedia...
The divergence is property of a point in space. Is that right?
If the divergence is zero at a point, that means that such point does not contribute with the field as source nor a sink. Is that right?
So, the divergence of a point measures how that point contributes as a source or a sink with the field?
The surface integral in the equation above means a certain area, right? Is that area the area of the entire surface (like a gaussian surface in the gauss's law) or the area of the micro-surface that is "around" the point I'm measuring the divergence on?
Usually I like to think in the dimensions of the conceps (units). I noticed that the unit of divergence will always be area/volume (m^-1). Does that have any meaning?
If someone can help me with some of these questions I would be grateful...
Thank you,
Rafael Andreatta