- Thread starter
- #1

Need someone to check my answers once more. (Promise this is the last time lol)

Draw the truth table corresponding to $f$(X,Y,Z) = \(\displaystyle \sum\)m(0,1,2,6,7)

Write out the canonical sum of products SOP expression for $f$(X,Y,Z) of problem above.

Minimize the expression above.

x!y!z!+x!y!z+x!yz!+xyz!+xyz = x!y!(z! + z) + y(x!z! + xz! + xz) --->

= y[z!(x! + x) + xz] = (x! + x) + xz = 1 + xz =

Draw the truth table corresponding to $f$(X,Y,Z)= POSM(1,2,3) (product of sums symbol M)

write out the canonical sums POS expression for $f(x,y,z) of the prob above.

minimize the expression...

Just need someone to check my answers and help me solve the last problem.

Don't know how to minimize it when I can't factor it out. I also have 9 terms.. So I need to distribute it?

thank you.

Sham

Draw the truth table corresponding to $f$(X,Y,Z) = \(\displaystyle \sum\)m(0,1,2,6,7)

**Answer:**

- x y z | f
- 0 0 0 |1
- 0 0 1 |1
- 0 1 0 |1
- 0 1 1 |0
- 1 0 0 |0
- 1 0 1 |0
- 1 1 0 |1
- 1 1 1 |1

Write out the canonical sum of products SOP expression for $f$(X,Y,Z) of problem above.

ANSWER:

x!y!z! + x!y!z + x!yz! + xyz! + xyzANSWER:

x!y!z! + x!y!z + x!yz! + xyz! + xyz

Minimize the expression above.

x!y!z!+x!y!z+x!yz!+xyz!+xyz = x!y!(z! + z) + y(x!z! + xz! + xz) --->

= y[z!(x! + x) + xz] = (x! + x) + xz = 1 + xz =

**x!y! + xz**?Draw the truth table corresponding to $f$(X,Y,Z)= POSM(1,2,3) (product of sums symbol M)

**ANSWER:**

- x y z | f
- 0 0 0 |1
- 0 0 1 |0
- 0 1 0 |0
- 0 1 1 |0
- 1 0 0 |1
- 1 0 1 |1
- 1 1 0 |1
- 1 1 1 |1

write out the canonical sums POS expression for $f(x,y,z) of the prob above.

ANSWER:

(x + y + z!)(x + y! + z)(x + y! + z!)ANSWER:

(x + y + z!)(x + y! + z)(x + y! + z!)

minimize the expression...

Just need someone to check my answers and help me solve the last problem.

Don't know how to minimize it when I can't factor it out. I also have 9 terms.. So I need to distribute it?

**HELP**thank you.

Sham

Last edited: