- Thread starter
- #1

#### Petrus

##### Well-known member

- Feb 21, 2013

- 739

I am working with an old exam

Solve this equation \(\displaystyle \sin^{-1}(x)+\cos^{-1}(2x)=\frac{\pi}{6}\)

progress:

I start take cos both side and I get

\(\displaystyle 2x+cos(\sin^{-1}(x))=\frac{\sqrt{3}}{2}\)

I draw it and call the bottom side for B and get

so we got

\(\displaystyle \sqrt{1-x^2}+2x=\frac{\sqrt{3}}{2}\)

Is this correct? (notice that I got problem solving this equation as well.)

Regards,

\(\displaystyle |\pi\rangle\)