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**[SOLVED]Trig problem: max square cut from circle**

Since this one is homework related, ill ask this as a procession so that I can make sure that I am grasping the logic.

the question is that with a round log with a diameter of 16cm, what is the strongest log that can be cut where the strength = width * depth^2.

So, I figured the biggest square would use the diameter. I have to use trig functions, so, I have the d as \(\displaystyle d= \sqrt{(16\sin(x))}\). Then I put \(\displaystyle w=16\cos(x)\)

because d is squared relative to w.

does the logic of this make sense so far? (Like the pic)

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